C Program to evaluate an expression

Note: This program is used to evaluate the expression ((a - b) / c * d + e) + (f + g);

Algorithm

Input: Input a,b,c,d,e,f,g
output: The expression is evaluated

1. Start
2. Input a,b,c,d,e,f,g
3. val = ((a-b)/c*d+e)+(f+g)
4. Print val
5. Stop

C Program

#include <stdio.h>

int main( )

{

   int a, b, c, d, e, f, g, val;

    printf("Enter first number: ");

    scanf("%d", &a);

    printf("Enter second number: ");

    scanf("%d", &b);

    printf("Enter third number: ");

    scanf("%d", &c);

    printf("Enter forth number: ");

    scanf("%d", &d);

    printf("Enter fifth number: ");

    scanf("%d", &e);

    printf("Enter sixth number: ");

    scanf("%d", &f);

    printf("Enter seventh number: ");

    scanf("%d", &g);

    val = ((a - b) / c * d + e) + (f + g);

    printf("The expression evaluated and the value is %d", val);

   return 0;

}